total pomi notam cu t<br />tei=5/9×t<br />salcami=3/4×(t-5/9×t)<br />stejari=32<br />t=5/9×t+3/4×(t-5/9×t)+32<br />t = 5/9×t+3/4×4/9×t+32<br />t = 5/9×t+1/3×t+32<br />t = 8/9×t+32<br />t-8/9×t=32<br />1/9×t=32<br />t=32×9<br />t=288 pomi<br />deci avem:<br />tei=288×5/9=160<br />salcami=3/4×(288-160)=3/4×128=96<br />proba: 160+96+32=288<br />
|___|___|___|___|___||___|___|___|___| = t (9/9)
tei = 5/9 × t 3/4 din rest=salcami
Dupa cum se vede din desen, a ramas 1/9 care stim ca sunt 32
Daca 1/9×t=32 , atunci 9/9×t=32×9=288
Sper sa intelegi desenul.
