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Hello54
a fost răspuns

1)Descompuneti: a)2x la a doua +3a la a doua x-4ax-6a la a doua ; b)x la a doua+7x+12 ; c)x la a doua - 10x + 24 ; d)x la a doua - 3x - 4 ; e) x la a doua - x - 2

Răspuns :

Saoirse1
b)x²+7x+12=x²+3x+4x+12=x(x+3)+4(x+3)=(x+3)(x+4);;;c) x²-10x+24=x²-4x-6x+24=x(x-4)-6(x-4)=(x-4)(x-6);;;;d) x²-3x-4=x²-4x+x-4=x(x-4)+(x-4)=(x-4)(x+1);;;e) x²-x-2=x²-2x+x-2=x(x-2)+(x-2)=(x-2)(x+1)