👤
Liela
a fost răspuns

Ofer 15 puncte.

Rezolvati inectuatiile:

a) 2(x-0,2)< sau egal cu 1,8

b) 3(x+0,09)< sau egal cu 0,21

c)[4×(3x-0,9)]:1,5< sau egal cu 1,6.

Vreau cat mai repede si NU rezolvate direct. Multumesc!

Răspuns :

a) 1.8+0.2=2*2=4
b)0.21=0.09=0.30*3=0.90
c)la aceasta nu te pot ajuta 

Nitugheorghe57
a)2(x-0.2)≤1.8⇒2x-0.4≤1.8⇒2x≤1.8+0.4⇒2x≤2.2⇒x≤2.2/2⇒x=1.1
b)3(x+0.09)≤0.21⇒3x+0.27≤0.21⇒3x≤-0.27+0.21⇒3x≤0.06⇒x≤0.06/3⇒x=0.02
c)[4×(3x-0.9)]÷1.5≤1.6⇒
(12x-3.6)÷1.5≤1.6⇒12x-3.6≤-1.5×1.6⇒
12x-3.6≤2.4⇒12x≤3.6+2.4⇒12x=6⇔x=6/12⇔x3/6
sucees

Alte intrebari