Răspuns :
fie triunghiul ABC, unde AB=a, BC=a+1, AC=a+2
AB+AC=224cm a+a+2=224
2a=222
a=111 AB=111, BC=112, AC=113
triunghi = AB+BC+AC=111+112+113=336cm
AB+AC=224cm a+a+2=224
2a=222
a=111 AB=111, BC=112, AC=113
triunghi = AB+BC+AC=111+112+113=336cm
Se da:
triunghiul ABC
AB+BC=224 cm
BC=AB+1
AC=AB+2
____________
P(ABC)-?
Rezolvare:
1) D/e AB+BC=224 ⇒ (inlocuim) AB+AB+1=224
2AB=224-1
2AB=223
AB= 223/2
AB= 111,5
2)BC=AB+1
BC=111,5+1
BC=112,5
3)AC=AB+2
AC=111,5+2
AC=113,5
4)P (perimetrul)= AB+BC+AC⇒ P ABC=111,5+112,5+113,5⇒ P ABC=337,5
triunghiul ABC
AB+BC=224 cm
BC=AB+1
AC=AB+2
____________
P(ABC)-?
Rezolvare:
1) D/e AB+BC=224 ⇒ (inlocuim) AB+AB+1=224
2AB=224-1
2AB=223
AB= 223/2
AB= 111,5
2)BC=AB+1
BC=111,5+1
BC=112,5
3)AC=AB+2
AC=111,5+2
AC=113,5
4)P (perimetrul)= AB+BC+AC⇒ P ABC=111,5+112,5+113,5⇒ P ABC=337,5