sa incercam;
[(2^10)^8+6^5x3^7+(2^3)^2]:[(2^16+6^12:2^7+2^9]=
[(2^10x8+6^5x3^7+2^3x2)]:(2^5x16+6^12:2^7+2^9)=
(2^80+6^5x3^7+2^6):(2^80+6^12:2^7+2^9)=
(2^80+2^6+6^5x3^7):(2^80+2^7+2^9x6^12)=
(2^86+6^5x3^7):(2^96x6^12)=
(2^86+2^96):(6^5x6^12):3^7=
2^182:6^17:3^12