Răspuns :
2(x+1)+2(x-2)=(3x-1)(x-3)+2⇒2x+2+2x-4=3x²-9x-x+3⇒
4x-2=3x²-8x+3⇒
-3x²+4x+8x-2-5=0⇒
-3x²+12x-7=0.
sucees
4x-2=3x²-8x+3⇒
-3x²+4x+8x-2-5=0⇒
-3x²+12x-7=0.
sucees
2(x+1) + 2(x-2)(x+2) = (3x - 1)(x - 3) + 2
2x + 2 + 2(x² - 4) = 3x² - 9x - x + 3 + 2
2x + 2 + 2x² - 8 = 3x² - 10x + 5
2x + 2x² - 3x² + 10x = 5 - 2 + 8
12x - x² = 11
2x + 2 + 2(x² - 4) = 3x² - 9x - x + 3 + 2
2x + 2 + 2x² - 8 = 3x² - 10x + 5
2x + 2x² - 3x² + 10x = 5 - 2 + 8
12x - x² = 11