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Rezolvati ecuatiile:
a). 4[tex] x^{2} [/tex] - 4x+1= (2x-1)(x+1)
b). [tex] \frac{1}{ x^{2}+6x+9} [/tex] + [tex] \frac{1}{x+3} [/tex] = [tex] \frac{4}{9} [/tex]
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Răspuns :

Nitugheorghe57
a)4x²-4x+1=(2x-1)(x+1)⇒4x²-4x+1=2x²+2x-x-1⇒.4x²-4x+1=2x²+x-1⇒
4x²-2x²-4x-x+2=0⇒
2x²-5x+2=0.
a=2
b=-5
c=2
Δ=b²-4ac⇒25-16⇒Δ=9⇒√Δ=√9⇒Δ=3
x1x2=-b+-√Δ/2a⇒5+3/4⇒8/4⇒x1=2
x2=5-3/4⇒2/4⇒x2=1/2
sucees


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