1.a)V=0.5L=500cm3
Cp=20%
ro(densitatea)=1.28g/ml(cm3)
ro=ms/V => ms=ro*V=1.28g/cm3*500cm3=640g=>ms=640g
Cp=md/ms*100=> md=Cp*ms/100=20*640/100=128g NaOH
b)Cp=20%
ms=40g
Cp=md/ms*100=>md=Cp*ms/100=8g zahar
ms=md+mH2O => MH2O=ms-md=40-8=32g H2O
c)ms=200g
Cp1=20% NaCl
Cpf=10%
Cp=md/ms*100=>md=Cp*ms/100=20*200/100=40g
ms=md+mH2O => MH2O=ms-md=200-40=160g H2O
20%..........160g H2O
10%...........xg
x=80g H2O necesar pentru a prepararea solutiei de concentratie 10%. Verifica