Răspuns :
x(3x-5)-2[tex]( x^{2} -4)[/tex]=
=[tex] 3x^{2} [/tex]-5x-[tex] 2x^{2} [/tex]+8=
=[tex] x^{2} [/tex]-5x+8
=[tex] 3x^{2} [/tex]-5x-[tex] 2x^{2} [/tex]+8=
=[tex] x^{2} [/tex]-5x+8
x(3x-5) - 2(x²-4)=0
3x²-5x-2x²+8=0
x²-5x+8=0
a=1
b=-5
c=8
Δ=b²-4ac=(-5)²-4*1*8=25-32=-7
Δ<0 rezulta ce ecuatia nu are solutii
3x²-5x-2x²+8=0
x²-5x+8=0
a=1
b=-5
c=8
Δ=b²-4ac=(-5)²-4*1*8=25-32=-7
Δ<0 rezulta ce ecuatia nu are solutii