[tex]6x^2 - 0,5x = 0|_{ \cdot 10} \Rightarrow 60x^2-5x = 0|_{: 5} \Rightarrow 12x^2 - x = 0 \Rightarrow
\\\;\\
\Rightarrow x(12x-1) = 0 \Rightarrow \begin{cases}x=0
\\\;\\
12x-1 = 0 \Rightarrow 12x = 1 \Rightarrow x = \dfrac{1}{12} \end{cases}[/tex]
Deci, ecuatia admite doua solutii:
[tex]x_1 = 0, \ \ x_2 = \dfrac{1}{12}[/tex]
