[tex]2^{2x}-13\cdot 6^{x-1}+9^x=0\\
2^{2x}-13 \cdot 3^{x}\cdot2^{x}\cdot\frac{1}{6}+3^{2x}=0 |\cdot6\\
6\cdot (2^x)^2-12\cdot 3^x\cdot2^x+6\cdot (3^x)^2-3^x\cdot 2^x=0\\
6(2^x-3^x)^2=3^x\cdot2^x\\
(2^x-3^x)^2=\frac{6^x}{6}\\
(2^x-3^x)^2=6^{x-1}\\
Nu\ stiu\ mai\ departe\
[/tex]
