[tex] M_{HCl} [/tex] = [tex] A_{H} [/tex] + [tex] A_{Cl} [/tex]
= 1+35
= 36
[tex] M_{NaHCO3} [/tex] = [tex] A_{Na} [/tex] + [tex] A_{H} [/tex] + [tex] A_{C} [/tex]+3·[tex] A_{O} [/tex]
= 23 + 1 + 12 + 3·16
=24 + 12 + 48
= 84
[tex] M_{Ca3(PO)4} [/tex] = 3·[tex] A_{Ca} [/tex] + 4·[tex] A_{P} [/tex]+ 4·[tex] A_{O} [/tex]
=3·40 + 4·30 + 4·16
= 120 + 120 + 64
= 304
