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a fost răspuns

simplificati raportul x^2-2x+1
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x^2-5x+4

Răspuns :

GreenEyes71

[tex]\dfrac{x^2-2x+1}{x^2-5x+4}=\dfrac{x^2-x-x+1}{x^2-x-4x+4}=\dfrac{x(x-1)-(x-1)}{x(x-1)-4(x-1)}=\\\\=\dfrac{(x-1)^2}{(x-1)(x-4)}=\dfrac{x-1}{x-4}.[/tex]

Green eyes.

HerminaAnaMaria
x²-2x+1=(x-1)²
x²-5x+4=x²-x-4x+4=x(x-1)-4(x-1)=(x-1)(x-4)
⇒(x²-2x+1)/(x²-5x+4)=(x-1)²/(x-1)(x-4)=(x-1)/(x-4)

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