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Ajutatima si pe mine plss. Calculati: 3×a-3×b+3×c, stiind ca:

a=(5+5÷5+2-2÷2)×2

b=[36-16÷(25÷5-12÷3)]÷5-4

c=7+3×[2-27÷(5×5+2÷1)]

Răspuns :

Raducustoica1
a = (5+1+2-1)*2 = 7*2 = 14
b = [36-16:(5-4)]:5-4 = (36-16:1):5-4 = (36-16):5-4 = 20:5-4 = 4-4 = 0
c = 7+3*[2-27:(25+2) = 7+3*[2-27:27) = 7+3*(2-1) = 7+3*1 = 7+3 = 10
3*a+3*b+3*c = 3*14+3*0+3*10 = 42+0+30 = 72

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