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a fost răspuns

Descompuneti in factori,grupand convenabil termenii:
a) x³+x²+x+1
b) x³+3x²-x-3
c) x³-2x²-x+2
d) x³-3x²-4x+12

Răspuns :

Renatemambouko
a) x³+x²+x+1=x²(x+1)+(x+1)=(x+1)(x²+1)
b) x³+3x²-x-3=x²(x+3)-(x+3)=(x+3)(x²-1)=(x+3)(x-1)(x+1)
c) x³-2x²-x+2=x²(x-2)-(x-2)=(x-2)(x²-1)=(x-2)(x-1)(x+1)
d) x³-3x²-4x+12 =x²(x-3)-4(x-3) =(x-3)(x²-4)=(x-3)(x-2)(x+2)







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