formula moleculara generala a hidrocarburii aromatici este: CnH2n-6
MCnH2n-6 = 12n + 2n - 6 = (14n-6) g/mol
(14n-6) g hidrocarbura aromatica mononucleara...(2n-6) g H
100 g hidrocarbura aromatica mononucleara...8.7 g H
(2n-6)*100 = 8.7(14n-6)
200n - 600 = 121.8n -52.2
78.2 n = 547.8
n= 547.8/78.2 = 7
=>C7H8 (toluenul)
