x,y,z
4,5,7 (direct proportionale)
x+y+z=64
[tex] \frac{x}{4}= \frac{y}{5} = \frac{z}{7} = \frac{x+y+z}{4+5+7} = \frac{64}{16}
[/tex]
[tex] \frac{x}{4} = 4 , x=4x4=16[/tex][tex] \frac{y}{5}=4, y=4x5=20 [/tex][tex] \frac{z}{7}=4 , z=4x7=28 [/tex]
sper ca te.am ajutat
