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Descompuneti in factori:
a) 5x+10=
b)16x²-9=
c)x²-10x+25=
d)(3x+1)(x-2)-(3x+1)(x+2)=
e)(x-y)²-16x²+8x-1=
f)(x+3)²-(x-5)²=

Răspuns :

Renatemambouko
a) 5x+10=5(x+2)
b)16x²-9=(4x-3)(4x+3)
c)x²-10x+25=(x-5)²
d)(3x+1)(x-2)-(3x+1)(x+2)=(3x+1)(x-2-x-2)=-4(3x+1)=
e)(x-y)²-16x²+8x-1=(x-y)²-(4x-1)²=(x-y-4x+1)(x-y+4x-1)=
=(-3x-y+1)(5x-y-1)
f)(x+3)²-(x-5)²=(x+3-x+5)(x+3+x-5)=8(2x-2)=16(x-1)

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