Răspuns :
Deci, in o cursa, primiul camion poate sa transporte pe cursa 10t.
Asadar, 10tx6=60t
Asadar, 10tx6=60t
x cantitate nisip .............. 6 curse ........... y tone camion 1
x cantitate nisip .............. 5 curse........... y+10 tone camion 2
6 * y = 5*(y+10) = x
6y-5y=50
y=50 camion 1 = 50 tone
camion 2 = 60 tone
50tone/cursa * 6 curse = 300 tone nisip.
60tone/cursa * 5 curse = 300 tone nisip
x cantitate nisip .............. 5 curse........... y+10 tone camion 2
6 * y = 5*(y+10) = x
6y-5y=50
y=50 camion 1 = 50 tone
camion 2 = 60 tone
50tone/cursa * 6 curse = 300 tone nisip.
60tone/cursa * 5 curse = 300 tone nisip