[tex]t_1=11:00 \\ t_2=11:45 \\ v_1=1 \ m/s=3,6 \ km/h \\ v_2=54 \ km/h\\ d=54 \ km \\ \boxed{t_3-?} \\ \boxed{t_4-?} \\ \boxed{\Delta t_2-?} \\ \bold{Rezolvare:} \\ \boxed{v=\frac{d}{t}} \\ t_3=t_1+\frac{d}{v_1}=11:00+\frac{54 \ km}{3,6 \ km/h} =11:00+15:00 \\ \Rightarrow \boxed{t_3=26:00=02:00 \ (a \ doua \ zi)} \\ t_4=t_2+\frac{d}{v_2}=11:45+\frac{54 \ km}{54 \ km/h}=11:45+1:00 \\ \Rightarrow \boxed{t_4=12:45} \\ \Delta t_2=t_3-t_4=26:00-12:45 \\ \Rightarrow \boxed{\Delta l_2=13:15} [/tex]
[tex]Rezulta \ ca \ primul \ va \ ajunge \ motociclistul, \ iar \\ biciclistul \ va \ ajunge \ cu \ \Delta t_2=13 \ ore \ si \ 15 \ min \ mai\ tarziu.[/tex]
