Răspuns :
20 min = 1200s
Q = UIt => I = Q/Ut = 1050000J/220·1200 = 3,977A
P = UI = 220V · 3,977A = 875W
Energia consumata in 1/3 ore = 0,875kWh/3 = 0,2917kwh
Costul va fi 1,60lei/kWh × 0,2917Kwh = 0,47lei.
Q = UIt => I = Q/Ut = 1050000J/220·1200 = 3,977A
P = UI = 220V · 3,977A = 875W
Energia consumata in 1/3 ore = 0,875kWh/3 = 0,2917kwh
Costul va fi 1,60lei/kWh × 0,2917Kwh = 0,47lei.
[tex]U=220 V \\ t=20 \ min=1 \ 200 \ s= 0,3 \ h \\ Q=1,05 \ MJ=1 \ 050 \ 000 \ J \\ n=1,60\ lei/kW \cdot h \\ \boxed{n_1-?} \\ \boxed{P-?} \\ \boxed{I-?} \\ \bold{Rezolvare:} \\Q=L\\ \boxed{ P=\frac{L}{t}=\frac{Q}{t}} \\ P=\frac{1 \ 050\ 000 \ J}{1\ 200 \ s} \\ \Rightarrow \boxed{P=875 \ W} \\ P=I \cdot U \Rightarrow I=\frac{P}{U} \\ I=\frac{875 \ W}{220 \ V} \\ \Rightarrow \boxed{I=4 \ A} \\ n_1=L \cdot n} \\ L=P \cdot t=875 \ W \cdot 0,3 \ h=0,875 \ kW \cdot 0,3 \ h \\ L=0,2625 \ kW \cdot h [/tex]
[tex]n_1=0,2625 \ kW \cdot h \cdot 1,60 \ lei/kW \cdot h \\ \Rightarrow \boxed{n_1=0,42 \ lei}[/tex]
[tex]n_1=0,2625 \ kW \cdot h \cdot 1,60 \ lei/kW \cdot h \\ \Rightarrow \boxed{n_1=0,42 \ lei}[/tex]