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Mslexy
a fost răspuns

x la puterea a 3-3x-2......urgent*coroana

Răspuns :

Vic04usea
x³-3x-2=x³-2x-x-2=-2(x+1)+ x(x²-1)=-2(x+1)+x(x-1)(x+1)=(x+1)[-2+x(x-1)]=(x+1)(x²-x-2)=(x+1)(x²-2x+x-2)=(x+1)[x(x+1)-2(x+1)]=(x+1)(x+1)(x-2)=(x-2)(x+1)²

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