[tex]\{x,y\}i.p.\{3,2(4)\}\Rightarrow \frac{x}{\frac{1}{3}}}=\frac{y}{\frac{1}{2,(4)}}} \Rightarrow 3x=\frac{9y}{22}=k\Rightarrow \\
\\ \Rightarrow x=\frac{k}{3},y=\frac{22k}{9}\\
\frac{x+y}{2}=263\\
\frac{k}{3}+\frac{22k}{9}=526| *9\\
3k+22k=4734\\
25k=4374\\
k=189,36\\
x=\frac{k}{3}=63,12\\
y=\frac{22k}{9}=462,88[/tex]
