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va rogg urgent
calculati perietru unui poligon  convex cu laturile  de
a)[tex]7 \frac{1}{3} cm6,(2)cm:6cm:7(8)cm[/tex]
b)[tex]8 \sqrt{3cm} : \sqrt{300} cm : \sqrt{192} cm : \sqrt{243} cm[/tex]

Răspuns :

Matepentrutoti
[tex]a)P= \frac{22}{3} +6 \frac{2}{9} +6+7 \frac{8}{9} =\\ = \frac{22}{3} + \frac{56}{9} +6+ \frac{71}{9}=\\ = \frac{66}{9} +\frac{56}{9}+ \frac{54}{9} +\frac{71}{9}= \frac{247}{9} \\ b)P=8 \sqrt{3} +10 \sqrt{3}+ 8 \sqrt{3} +9 \sqrt{3} =35 \sqrt{3} [/tex]Scrie răspunsul tău aici
MFM
22/3+56/9+6+71/9 =
daca 7(8)=7,(8)
(66+56+54+71)/9=245/9
b) 8√3+10√3+8√3+9√3=35√3

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