M,KClO3= (39gK + 35,5gCl+3x16gO)/mol= 122,5g/mol
M,KCl=(39gK+35,5gCl)=74,5g/mol
- notez cu a nr. moli de clorat si de clorura din amestec
a,molx(122,5+74,5)g/mol=19,7-g--> a= 0,1mol din fiecare sare
-cum in fiecare mol de sare se gaseste cate 1 mol de ion potasiu,sunt, in total, 0,2mol ioniK=
-1MOL ion.........are.....6,023x10²³ioni
0,2mol................................N= 0,2x6,023X10²³ioni potasiu calculeaza!
