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Prislea2003
a fost răspuns

Impartiti numarul 106 in trei parti direct proportionale cu 0,(3), 2 , 1,2

Răspuns :

0,(3)=3/9=1/3
{=>x=k/3
{=>y=2k
{=>z=1,2k
x+y+z=106
k/3+2k+1,2k=106
k+6k+3,6k=318
10,6k=318=>k=30
x=k/3=30/3=>x=10
y=2k=2×30=>y=60
z=1,2k=1,2×30=>z=36

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