(a,b,c) d.p. (1,(4);1,(5);1,(6)
a=[tex] \frac{14-1}{9} = \frac{13}{9} K [/tex]
b=[tex] \frac{15-1}{9} = \frac{14}{9} K[/tex]
c=[tex] \frac{16-1}{9} = \frac{15}{9} K[/tex]
a+b+c=84
[tex] \frac{13K}{9} + \frac{14K}{9} + \frac{15K}{9} =84[/tex]
[tex] \frac{42K}{9} =84[/tex]
42K=84x9
42K=756
K=756:42
K=18
a=[tex]18x \frac{13}{9} = \frac{18x13}{9} = \frac{234}{9}=26 [/tex]
b=[tex]18x \frac{14}{9} = \frac{18x14}{9} = \frac{252}{9} =28[/tex]
c=[tex]18x \frac{15}{9} = \frac{18x15}{9} = \frac{270}{9} =30[/tex]
