2a=3b=4c = k 2a = k, a = k/2 3b = k, b = k/3 4c = k, c = k/4 a+b+c = 130 k/2+k/3+k/4 = 130 6k+4k+3k = 1560 ( am adus la acelasi numitor comun, acesta fiind 12) 13k = 1560 k = 1560:13 k = 120 a = k/2 = 120/2 = 60 b = k/3 = 120/3 = 40 c = k/4 = 120/4 = 30
