Răspuns :
pret creion x
pret pix y
5x+3y=19
3x+6y=24
inmultim prima ecuatie cu 2 si obtinem
10x+6y=19*2=38
apoi scade a doua ecuatie din prima si rezulta
10x+6y-(3x+6y)=38-24
10x+6y-3x-6y=14
7x=14
x=14:7=2
5*2+3y=19
3y=19-10=9
y=9:3=3
deci nr creioane=2, nr.pixuri =3
verificare 5*2+3*3=10+9=19 ok
3*2+6*3=6+18=24 ok
pret pix y
5x+3y=19
3x+6y=24
inmultim prima ecuatie cu 2 si obtinem
10x+6y=19*2=38
apoi scade a doua ecuatie din prima si rezulta
10x+6y-(3x+6y)=38-24
10x+6y-3x-6y=14
7x=14
x=14:7=2
5*2+3y=19
3y=19-10=9
y=9:3=3
deci nr creioane=2, nr.pixuri =3
verificare 5*2+3*3=10+9=19 ok
3*2+6*3=6+18=24 ok
notam creioanele cu c si pixurile cu p
si avem :
5c+3p=19lei
3c+6p=24lei
5c+3p=19lei=> 3p=19-5c
3c+3p+3p=24
3c+19-5c+19-5c=24
-7c+38=24
-7c=24-38
-7c=-14
c=-14\-7
c=2
si avem :
5c+3p=19lei
3c+6p=24lei
5c+3p=19lei=> 3p=19-5c
3c+3p+3p=24
3c+19-5c+19-5c=24
-7c+38=24
-7c=24-38
-7c=-14
c=-14\-7
c=2