2mol 2mol. x mol
BaCl2+2AgNO3→Ba(NO3)2+2AgCl
1mol. 2mol. 1mol
2mol/2 mol=x mol/1 mol
x mol=2 mol*1 mol/2 mol=1 mol=v(Ba(NO3)2)=1mol
cantitatea de substanta v=m/M→m=v*M
M(Ba(NO3)2)=137+2*14+6*16=137+28+96=261 g/mol
m(Ba(NO3)2)=1 mol *261 g/mol=261 g
Raspuns:v=1 mol
m=261 g
Succese !!!
