Răspuns :
daca (a;b) i.p. (3;8) <=> 3a=8b = ... k deci: a=k/3 si b=k/8 !
dar m(a)=(a+b)/2=27,5 adica; a+b=27,5*2 = 55
=> a+b = k/3 + k/8=55 |*(3*8=24)
8k+3k=1320 de unde k = 1320/11=120
=> a=120/3=40 si
b=120/8=15
dar m(a)=(a+b)/2=27,5 adica; a+b=27,5*2 = 55
=> a+b = k/3 + k/8=55 |*(3*8=24)
8k+3k=1320 de unde k = 1320/11=120
=> a=120/3=40 si
b=120/8=15