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Calculati:
a) (6x la a doua - 1 )(2x-2 )
b) (x-3)(x la a doua- 2x +2 )
c) (3x-5)(3x+5)
d) ( x la a doua - 5x + 6 )(x la a doua-5x + 4 )
e ) ( x la a doua +2x-6)(2x la doua - x -3 ) .
Va rog , am nevoie urgent.

Răspuns :

Lera13
a) ( 6x²-1)( 2x-2)=0⇔(36x²-18x+1)(2x-2)=0⇔(72x³-72x²-36x²+36x+2x-2)=0⇔72x³-108x²+38x-2=0
cred ca asa

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