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Punctu b... Rezolvati in r ecuatia bipatrata

Punctu B Rezolvati In R Ecuatia Bipatrata class=

Răspuns :

Vic04usea
x⁴+5x²+4=0
t=x²
→ t²+5t+4=0
a=1
b=5
c=4
∆=b²-4ac
∆=5²-4*1*4=25-16=9

t1=(-b+√∆)/2a=( -5+√9)/2*1=(-5+3)/2=-2/2=-1

t2=(-b-√∆)/2a=(-5-3)/2=-8/2=-4

→x²=-1 sau x²=-4
x=∅
S=∅
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