Răspuns :
pur si simplu faci f(x)=g(x)
3x-5 = 2x+1
x=6
si inlocuiesi in oricare
f(6)=13 = g(6)
prin urmare punctul de intersecie M(6,13)
f:R⇒R, f(x)=3x-5 f(x)=g(x) f(6)= 3·6- 5
g:R⇒ R, g(x)=2x+1. 3x- 5= 2x+ 1 =18- 5
_________________
3x- 2x= 1+ 5 =13
f(x) ∩ g(x)= A( x, y)
x= 6 g(6) = 2·6+ 1
= 12+ 1
= 13
A( 6; 13)
g:R⇒ R, g(x)=2x+1. 3x- 5= 2x+ 1 =18- 5
_________________
3x- 2x= 1+ 5 =13
f(x) ∩ g(x)= A( x, y)
x= 6 g(6) = 2·6+ 1
= 12+ 1
= 13
A( 6; 13)