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Nikyroscata
a fost răspuns

(x+1)la pătrat +3(x+1)...............alt exercitiu 4(x-2) la pătrat -3(2-x) ....alt exercitiu x(x-2)-y(2-x)+x-2..... Alt exercitiu (a-b)(2x-3y)-(a-b)(3x+4y)....si alt exercitiu (x-3)(x+7y)+(3x+5y)(3-x)

Răspuns :

Renatemambouko
(x+1)²+3(x+1)= (x+1)(x+1+3)=(x+1)(x+4)

4(x-2)² -3(2-x)=4(x-2)² +3(x-2)=(x-2)(4x-8+3)=(x-2)(4x-5)

x(x-2)-y(2-x)+x-2=x(x-2)+y(x-2)+(x-2)=(x-2)(x+y+1)

(a-b)(2x-3y)-(a-b)(3x+4y)=(a-b)(2x-3y-3x-4y)=(a-b)(-x-7y)=(b-a)(x+7y)

(x-3)(x+7y)+(3x+5y)(3-x)=(x-3)(x+7y)-(3x+5y)(x-3)=
=(x-3)(x+7y-3x-5y)=(x-3)(-2x+2y)=2(x-3)(y-x)












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