👤
Ioanamariarus2002
a fost răspuns

E (x)=(2/x-1-1/x+1):[(x+3)(x-1)/x^2-2x+1]

Răspuns :

Renatemambouko
E (x)=[2/(x-1)-1/(x+1)]:[(x+3)(x-1)/(x²-2x+1)] =
=(2x+2-x+1)/(x-1)(x+1) :[(x+3)(x-1)/(x-1)²] =
=(x+3)/(x-1)(x+1) :(x+3)/(x-1) =
=(x+3)/(x-1)(x+1) × (x-1)/(x+3) =
=1/(x+1) × 1/1 =
=1/(x+1)

Alte intrebari