1. Daca AB=CD =12 cm
si <B=120°=> <C=(360°-2*120):2=60°=> ΔCDB=echilateral=> BD=12 cm
2. Daca AB=12 cm şi BC=8cm
stim ca Ab=CD si BC=Ad=>
Perimetrul ABCD=2*(AB+BC)=2*(12+8)=2*20=40 cm
3.<D=11=,A
=> <C=(360°-2*11):2=169°
4.AC_|_AD<D=60 si AD=6
paralelogramul cu diagonalele perpendiculare este romb
=> Perimetrul este 6*4=24 cm
5.<C=3/5*D =>D=5/3*C
<C*2+<D*2=360°
2*C+2*5/3*C=360° |*3
6C+10C=1080°
16C=1080°
<C=67,5°=<A
6.CD=AD+24
P=168 cm
P=(CD+AD)*2=(AD+24+AD)*2=(2AD+24)*2=4AD+48
4*AD+48=168
AD=(168-48):4=30
CD=30+24=54 cm