Care ii formula ca o stiu eu ..
Formula : Be(NO3)2
R masa = Be:N2:O6
9:28:96
R atomic = Be : N2 :O6
1 :2 :6
Masa Be(NO3)2=9+28+96=133
In 133 g Be(NO3)2 ..........9 g Be ...........28 g N2 .............96 g O2
In 100 g Be(NO3)2 ...........x g ................y gN2 ..............z g O 2
x = (100×9)÷133⇒x=6,76%
y=(100×28)÷133⇒y=21,05%
z=(96×100)÷133⇒z=72,18%
raportul de masa,raportul atomic ,compozitia procentuala la azotatul de beriliu
cred ca asa erau altele nu stiu
