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Andreeazamfir
a fost răspuns

calculati 3,5 la putere 2 - 1,2 *{11+1,1*[6,5+2*(0,45-0,4)]}

Răspuns :

Georgi765
3,5^2-1,2x{1,1+1,1x[6,5+2x(4,5-0,4)]}=
=12,35-1,2x[1,1+1,1x(6,5+2x4,1)]
=12,35-1,2x[1,1+1,1x(6,5+8,2)]
=12,35-1,2x(1,1+1,1x14,4)
=12,35-1,2x(1,1+15,84)
=12,35-1,2x16,94
=12,35-20,328
= -7,978