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Djvictor
a fost răspuns

rezolvati in R inecuatia:
(2-x)(5x-1) asupra x²+2 totul ≥0

Răspuns :

Nitugheorghe57
(2-x)(5x-1)/x²+2≥0⇒
10x-2-5x²+x/x²+2≥0⇒
-5x²+11x-2≥x²+2⇒
-6x²+11x-4≥0
a=-6
b=11
c=-4
Δ=b²-4ac⇒Δ=(11)²-4×(-6)×(-4)⇒
Δ=121-69⇒Δ=25⇒√Δ=√25⇒Δ=5
x1x2=-b+-√Δ/2a
x1=-11+5/-12=-6/-12⇒x1=-1/-6
x2=-11-5/-12⇒-16/-12⇒x2=-8/-6⇒-4/-3
sucees

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