sim B/ sin C=1
sin B=AC/BC SI BC=6⇒ sin B=AC/6
sin C=AB/BC si BC=6⇒sin C=AB/6 din astea doua ⇒ sin B/sin C=1⇔AC/6 totul supra AB/6=1⇔AC/6: AB/6=1⇔AC/6×6/AB=1⇔AC/AB=1 deci AC=AB deci triunghiul ABC isoscel
aplic teorema lui Pitagora
AB²+AC²=BC²
daca AB=AC⇒AB²+AB²=6²⇒2AB²=36⇒AB²=36/2⇒AB²=18⇒AB=√18⇒AB=3√2 deci AC=3√2
