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Ce puritate are 45 kg carbid, care in reactie cu apa formeaza 20 m^3 acetilena, la 127 grade celsius si 800 mm Hg?

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Alexandrutopor2
CaC2+2H20=>Ca(OH)2+C2H2 
P*V=nRT=>n C2H2= P*V/R*T=1,05263*20000/0,082*400=641,84 moli C2H2
P=800/760=1,05263 atm
V=20m^3 acetilena= 20000 dm^3=20000 l
T=400K
n carbid= 641,84 moli=>m CaC2= 41077,76 g 
M CaC2=64 g/mol
p=41077,76/45000*100=91,28% 

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