M.C6H6= (6X12gC+6gH)/mol=78g/mol
M,HNO3=)(1gH+14gN+48gO)mol= 63g/mol
M, nitrobenzen=(6x12gC+5gH+14gN+32gO)/mol=123g/mol
- din reactie,
1mol benzen........1mol HNO3........1mol nitrobenzen
78g........................63g.........................123g
56...............................m...................................m'
m=45,23gHNO3-->este md din solutie 63/100=45,23/ms---> ms=
m'=88,3g nitrobenzen , daca randamentul este 100%; fiind mai mic, se va obtine o masa mai mica-->m'=88,3x80/100------------------->
calculeaza !!!!!
