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Stiind ca a+b+c=13, calculeaza:
a) 3a+3b+3c;
b) 5a+5b+5c+12;
c) 10a+10b+10c-100;
d) 11a+11b+11c+309;
e) 1000-(25a+25b+25c);
f) a+(b+c).
Tema este pentru clasa a treia

Răspuns :

Mihaisoare11

a) 3(a+b+c)=3x13=39
b)5(a+b+c)+12=5x13+12=65+12=77
c)10(a+b+c)-100=10x13-100= 130-100=30
d)11(a+b+c)+309=11×13+309=143+309= 452
f)1000-25(a+b+c)=1000-25×13=1000-325=675
e) a+(b+c)=a+b+c=13

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