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a fost răspuns

Descompuneti in factori: a)3x la a doua-24xy+48y
b)18 ax la a doua +24ax+8a
c)49x la a doua y la a doua + 14 y la a 2 x+ y la a 2

Răspuns :

3x² - 24xy + 48 y² = 

= 3(x² - 8y + 16y²)

= 3(x - 4y)²

= 3(x - 4y)(x - 4y)


18ax² + 24ax + 8a = 

= 2a(9x² + 12x + 4) 

= 2a(3x + 2)²

= 2a(3x + 2)(3x + 2)


49x²y² + 14 y²x + y² = 

= y²(49x² + 14x + 1)

= y²(7x + 1)²

= y²(7x + 1)(7x + 1)
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