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a fost răspuns

(2x-3)(3x+2)+(2x-1)(3x-2)-2x(x-3)

Răspuns :

Ale0128
6x^2+4x-9x-6+6x^2-4x-3x+2-2x^2+6x=0
10x^2-6x-4=0 |:2
5x^2-3x-2=0
d (delta)= 9+40=49
x1=(3+7)/10=1
x2=(3-7)/10=-2/5
ps asta e daca ecuatia =0
Nitugheorghe57
(2x-3)(3x+2)+(2x-1)(3x-2)-2x(x-3)⇒
(6x²+4x-9x-6)+(6x²-7x+2)-(2x²-6x)⇒
(6x²-5x+6)+(6x²-7x+2)-(2x²-6x)⇒
6x²-5x-6+6x²-7x+2-2x²+6x=⇒
10x²-6x-4=0
a=10
b=-6
c=-4
Δ=b²-4ac⇒Δ=6=36+160⇒Δ=196⇒√Δ=√196⇒Δ=14
x1x2=-b+-√Δ/2a
x1=6+14/20⇒20/20⇒x1=1
x2=6-14/20⇒-8/20⇒x2=se fac simplificari⇒-2/5
sucees