[tex]\displaystyle \\
3x^2 -x-2=0 \\ \\
\texttt{Folosim formula: } x_{12}= \frac{-b \pm \sqrt{b^2-4ac} }{2a} \\ \\
\texttt{Rezolvare: } \\ \\
x_{12}= \frac{1 \pm \sqrt{1-4\cdot 3 \cdot (-2)} }{2\cdot 3}= \frac{1 \pm \sqrt{25} }{6}=\frac{1 \pm 5 }{6} \\ \\
x_1 = \frac{1 + 5 }{6} = \frac{6 }{6}=\boxed{1} \\
x_2 = \frac{1 - 5 }{6} = \frac{-4 }{6}=\boxed{- \frac{2}{3} } [/tex]
