1. CO₂+2NaOH=Na₂CO₃+H₂O
faci 40 supra o suta = x supra 8
x=40 * 8 supra 100
x=3,2
M NaOH=23+16+1=40g/mol
M CO₂=12+2*16=44g/mol ( M= mAsa molara)
x=masa de CO₂ reactionata
x=3.2*44/2*40
x=1.76g CO₂
2. MgCO3 ----->MgO +CO2 (1)
MgO +H2SO4 -----> MgSO4+ H2O (2)
CO2+ Ca(OH)2 -----> CaCO3+ H2O (3)
1mol MgCO3 ---> 1mol MgSO4 <---> 1mol CaCO3
84g MgCO3............120 g MgSO4...........100g CaCO3 336g........................x.................................y
x=480g
y=400g
