Răspuns :
d=213m
t=1min=60s
v=[tex] \frac{d}{t} [/tex]
v=[tex] \frac{213m}{60s} [/tex]
v=3,55m/s
t=2min
v=3,55m/s
d=vt=3,55m/s*120min=3,55m/s*7200s
d=25560m
Intr-un interval de 2 ore (120 minute-7200 secunde) iepurasul parcurge 25560 metri.
t=1min=60s
v=[tex] \frac{d}{t} [/tex]
v=[tex] \frac{213m}{60s} [/tex]
v=3,55m/s
t=2min
v=3,55m/s
d=vt=3,55m/s*120min=3,55m/s*7200s
d=25560m
Intr-un interval de 2 ore (120 minute-7200 secunde) iepurasul parcurge 25560 metri.