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daca 5x+4y+3z=112,32si 2x+y=144supra 5
Aflati suma x+y+z

Răspuns :

Renatemambouko
5x+4y+3z=112,32
2x+y=144/5
5x+4y+3z-2x-y=112,32-144/5
3x+3y+3z=83.52
3(x+y+z)=83,52
x+y+z=83,52/3
x+y+z=27,84

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